Пифагорова теорема как пишется - Граматика и образование на Pisanino.ru

Орфограммы.

№ 16. Большая буква и кавычки в собственных наименованиях.

ПРАВИЛО.

С большой буквы пишется следующие слова.

· Имена, отчества, фамилии: Сергеев, Андрей Викторович.

· Прозвища, псевдонимы: Антоша Чехонте, Шустрый.

· Клички животных: Мурка, Шарик.

· Названия божеств и мифологических существ: бог Ярило, Перун.

· Официальные и неофициальные названия государств: Российская Федерация. Англия, Приднепровье, Запорожье.

· Названия высших государственных, правительственных и международных организаций и должностей: Президент России, Государственная Дума РФ, Совет Безопасности.

· Географические и астрономические названия (кроме родовых понятий): озеро Байкал, пустыня Сахара, планета Марс.

· В названиях, начинающихся на Северо- (и Северно-), Юго- (и Южно-), Восточно-, Западно-, Центрально-, с прописной буквы пишутся (через дефис) оба компонента первого сложного слова: Северо-Байкальское нагорье, Восточно-Китайское море, Западно-Сибирская низменность, Центрально-Чернозёмный регион, Юго-Западный территориальный округ.

· Нарицательные существительные в составных географических названиях: архипелаг Новая Земля, бухта Золотой Рог, города Белая Церковь, Минеральные Воды, Царское Село .

· Служебные слова (артикли, предлоги, частицы), находящиеся в начале географических названий, пишутся с прописной буквы, напр.: улица Под Вязом, Лос-Анджелес, Лас-Вегас. Так же пишутся начальные части Сан-, Сен-, Сент-, Санкт-, Сайта-, : Сан-Диего, Санта-Барбара. НО служебные слова, находящиеся в середине географических названий, пишутся со строчной буквы: Ростов-на-Дону, Рио-де-Жанейро, Абруццо-э-Молизе.

С большой буквы в первом слове пишутся:

· названия государственных, партийных, общественных, профсоюзных учреждений, министерств, учебных заведений, договоров, соглашений: Московский государственный университет, Хельсинское соглашение, Камский автомобильный завод;

· названия краёв, областей, районов: Хабаровский край, Амурская область, округ Колумбия.

· В названиях исторических эпох, событий, знаменательных дат, религиозных праздников: Рождество, Великая Отечественная война (запомните, здесь два слова пишутся с большой буквы), День медицинского работника.

· В названиях памятников архитектуры, храмов, крепостей: Киево-Печерская лавра.

· В названиях орденов, наград, состоящие из нескольких слов (кроме родовых): орден Мужества, звание Героя России, орден Славы, медаль «За спасение утопающих», орден «Мать-героиня» (если название в кавычках, то с большой буквы пишется только первое слово).

· прилагательные, образованные от собственных личных имен:

помощью суффиксов-ов,-ев,-ов,-ев,-ин-,-в смысле принадлежности чего-то этому лицу: Светланины книги, Далев словарь, Шекспировы трагедии, Рафаэлева мадонна.

· прилагательные, образованные от собственных личных имен с

помощью суффиксов -овская,-евськ,-инськ,-инск-в значении «имени, памяти кого-то»: Пушкинские чтения; Петровские реформы, Строгановское училище, Нобелевская премия, Толстовские чтения, Шолоховская конференция.

· все буквы в аббревиатурах: РФ, ЗАГС, ТЭЦ;

· начальная часть Тер- в армянских фамилиях: Тер-Габриэлян, Тер-Петросян;

· названия персонажей в сказках, пьесах, баснях и некоторых других произведениях художественной литературы, фольклора: Красная Шапочка, Змей Горыныч, Серый Волк, Синяя Борода, Дед Мороз, Снегурочка.

· вторая часть сложных прилагательных типа дяди-Сашин, дяди-Стёпин, тёти-Ирин, бабы-Клавин.

Трудные случаи.

Пишутся со строчной буквы.

· Нарицательные, образованные от имён собственных, пишутся со строчной буквы, если герой отрицательный, и с большой, если он положительный.

Сравните:

обломовы, плюшкины, чичиковы.

Сколько таких Морозовых было в годы войны!

· Названия единиц измерения, данные по именам ученых : ампер, вольт, паскаль, рентген и т. п.

· Названия предметов, изделий (видов одежды, оружия, тканей, напитков и др.), данные по личным именам, названиям фирм, географическим названиям: макинтош, кольт, винчестер, бостон, бордо, хохлома, адидасы;

· Составные части арабских, тюркских, персидских имен, обозначающие социальное положение, родственные отношения и т. п., а также служебные слова (ага, ад, ал, аль, ас, ар, аш, бей, бек, заде, зуль, ибн, кызы, оглы, оль, паша, уль, хан, шах, эд, эль) , а также конечная часть -сан в японских собственных именах: Чио-Чио-сан, Турсун-заде, Хасан-бек.

· Названия должностей, званий, ученых степеней и т.д.: декан, народный артист России.

· Исторические события, понятия, названия которых стали нарицательными: гражданская война, античность, советская власть.

· Фразеологизмы: ахиллесова пята, ариаднина нить, каинова печать, прокрустово ложе, сизифов труд, гордиев узел, демьянова уха, тришкин кафтан, филькина грамота;

· Терминологические сочетания: рентгеновские лучи, пифагорова теорема.

· Родовые названия, относящиеся к религии и мифологии: ангел, архангел, херувим, домовой, леший, нимфа, русалка.

· Индивидуальные названия, употреблённые в качестве обобщенных названий животных: жучка, барбос (о собаках), савраска, сивка (о лошадях), бурёнка (о корове).

· имена прилагательные, образованные от личных имен и фамилий при помощи суффиксов -ск-, -овск- (-евск-), -инск-, пишутся со строчной буквы: ожеговский словарь, дарвиновское учение, бетховенская соната, шекспировские трагедии, пришвинская проза, лермонтовская поэзия, кутузовские традиции.

Названия праздников.

Рождество, Новый год

День Конституции, День учителя, НО день рождения.

Первое мая – 1-ое Мая.

Восьмое марта – Восьмое марта.

Произносите правильно:

· с Восьмым марта,

· с Первым сентября,

· с Девятым мая.

Употребление кавычек.

Заключаются в кавычки.

· Наименованиях чего-либо (произведения, фирмы, организации, кинотеатры, фестивали, клубы, печатные издания и т.д.): роман «Евгений Онегин», теплоход «Александр Суворов», фабрика «Заря», гостиница «Астория», клуб «Спартак», фестиваль «Молодые голоса», газета «Аргументы и факты».

· Названия партий и движений: «Яблоко» «Единая Россия».

· Названия отечественных информагенств: «Интерфакс», «Россия сегодня».

· Названия орденов, медалей, наград, знаков отличия: орден «Мать-героиня», медаль «Ветеран труда», премия «Оскар».

· Названия документов: Закон «Об образовании».

· Названия стихийных бедствий (ураганов, тайфунов, торнадо): тайфун «Джуди», ураган «Катрина», циклон «Сидр».

· Названия производственных марок технических изделий: автомобиль «Волга», стиральная машина «Индезит», газовая плита «Ардо».

· Названия техники: самолеты «Руслан», баллистическая ракета «Тополь».

· Названия названия интернет-ресурсов и веб-сервисов: «Яндекс», «Рамблер», справочно-информационных систем и компьютерных программ: системы «КонсультантПлюс».

· Названия продовольственных товаров: вафли «Сливочные», пирожное «Картошка», сыр «Моцарелла», кофе «Черная карта». Названия продуктов в бытовом употреблении пишутся со строчной буквы без кавычек: любительская колбаса, бородинский хлеб, салат оливье, пирожное картошка. Без кавычек со строчной буквы пишутся и названия сортов вин, минеральных вод и др. напитков: мерло, шардоне, рислинг, портвейн, боржоми.

· Названия видов и сортов сельскохозяйственных культур, овощей, цветов и т. п.: клубника «виктория», виноград «шардоне», тюльпан «черный принц». Обратите внимание: они пишутся со строчной буквы.

· Станции метрополитена: «Горки», «Дубравная».

· Условные названия жилых кварталов, массивов и отдельных домов, сопровождаемые словами жилой массив, ТСЖ (товарищество собственников жилья), СЖД (социальный жилой дом) и пр.: жилой массив «Светлый», жилой комплекс «Черёмушки», ТСЖ «Азинский», фермерское хозяйство «Залесный», подстанция «Южная».

· условные наименования автодорог, трасс,нефтепроводов, газопроводов и т. п.: автодорога «Дон», «Урал», «Крым», «Уссури», газопровод «Голубой поток», нефтепровод «Дружба».

ПРИМЕРЫ.

Пример № 1.

Пример № 2.

Пример № 3.

Материал подготовила: Мельникова Вера Александровна.

Источник

Pythagorean theorem


Type	Theorem
Field	Euclidean geometry
Statement	The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).
Symbolic statement	$a^{2}+b^{2}=c^{2}$
Generalizations	Law of cosines Solid geometry Non-Euclidean geometry Differential geometry
Consequences	Pythagorean triple Reciprocal Pythagorean theorem Complex number Euclidean distance Pythagorean trigonometric identity

In mathematics, the Pythagorean theorem or Pythagoras’ theorem is a fundamental relation in Euclidean geometry between the three sides of a right triangle. It states that the area of the square whose side is the hypotenuse (the side opposite the right angle) is equal to the sum of the areas of the squares on the other two sides. This theorem can be written as an equation relating the lengths of the sides a, b and the hypotenuse c, often called the Pythagorean equation:^[1]

$a^{2}+b^{2}=c^{2},$

The theorem is named for the Greek philosopher Pythagoras, born around 570 BC. The theorem has been proven numerous times by many different methods – possibly the most for any mathematical theorem. The proofs are diverse, including both geometric proofs and algebraic proofs, with some dating back thousands of years.

When Euclidean space is represented by a Cartesian coordinate system in analytic geometry, Euclidean distance satisfies the Pythagorean relation: the squared distance between two points equals the sum of squares of the difference in each coordinate between the points.

The theorem can be generalized in various ways: to higher-dimensional spaces, to spaces that are not Euclidean, to objects that are not right triangles, and to objects that are not triangles at all but n-dimensional solids. The Pythagorean theorem has attracted interest outside mathematics as a symbol of mathematical abstruseness, mystique, or intellectual power; popular references in literature, plays, musicals, songs, stamps, and cartoons abound.

Other forms of the theorem

If c denotes the length of the hypotenuse and a and b denote the two lengths of the legs of a right triangle, then the Pythagorean theorem can be expressed as the Pythagorean equation:

${displaystyle a^{2}+b^{2}=c^{2}.}$

If only the lengths of the legs of the right triangle are known but not the hypotenuse, then the length of the hypotenuse can be calculated with the equation

${displaystyle c={sqrt {a^{2}+b^{2}}}.}$

If the length of the hypotenuse and of one leg is known, then the length of the other leg can be calculated as

${displaystyle a={sqrt {c^{2}-b^{2}}}}$

${displaystyle b={sqrt {c^{2}-a^{2}}}.}$

A generalization of this theorem is the law of cosines, which allows the computation of the length of any side of any triangle, given the lengths of the other two sides and the angle between them. If the angle between the other sides is a right angle, the law of cosines reduces to the Pythagorean equation.

Proofs using constructed squares

Rearrangement proof of the Pythagorean theorem.
(The area of the white space remains constant throughout the translation rearrangement of the triangles. At all moments in time, the area is always c². And likewise, at all moments in time, the area is always a²+b².)

Rearrangement proofs

In one rearrangement proof, two squares are used whose sides have a measure of a+b and which contain four right triangles whose sides are a, b and c, with the hypotenuse being c. In the square on the right side, the triangles are placed such that the corners of the square correspond to the corners of the right angle in the triangles, forming a square in the center whose sides are length c. Each outer square has an area of ${displaystyle (a+b)^{2}}$ as well as ${displaystyle 2ab+c^{2}}$ , with 2ab representing the total area of the four triangles. Within the big square on the left side, the four triangles are moved to form two similar rectangles with sides of length a and b. These rectangles in their new position have now delineated two new squares, one having side length a is formed in the bottom-left corner, and another square of side length b formed in the top-right corner. In this new position, this left side now has a square of area ${displaystyle (a+b)^{2}}$ as well as ${displaystyle 2ab+a^{2}+b^{2}}$ . Since both squares have the area of ${displaystyle (a+b)^{2}}$ it follows that the other measure of the square area also equal each other such that ${displaystyle 2ab+c^{2}}$ = ${displaystyle 2ab+a^{2}+b^{2}}$ . With the area of the four triangles removed from both side of the equation what remains is ${displaystyle a^{2}+b^{2}=c^{2}.}$ ^[2]

In another proof rectangles in the second box can also be placed such that both have one corner that correspond to consecutive corners of the square. In this way they also form two boxes, this time in consecutive corners, with areas ${displaystyle a^{2}}$ and ${displaystyle b^{2}}$ which will again lead to a second square of with the area ${displaystyle 2ab+a^{2}+b^{2}}$ .

English mathematician Sir Thomas Heath gives this proof in his commentary on Proposition I.47 in Euclid’s Elements, and mentions the proposals of German mathematicians Carl Anton Bretschneider and Hermann Hankel that Pythagoras may have known this proof. Heath himself favors a different proposal for a Pythagorean proof, but acknowledges from the outset of his discussion «that the Greek literature which we possess belonging to the first five centuries after Pythagoras contains no statement specifying this or any other particular great geometric discovery to him.»^[3] Recent scholarship has cast increasing doubt on any sort of role for Pythagoras as a creator of mathematics, although debate about this continues.^[4]

Algebraic proofs

The theorem can be proved algebraically using four copies of the same triangle arranged symmetrically around a square with side c, as shown in the lower part of the diagram.^[5] This results in a larger square, with side a + b and area (a + b)². The four triangles and the square side c must have the same area as the larger square,

${displaystyle (b+a)^{2}=c^{2}+4{frac {ab}{2}}=c^{2}+2ab,}$

giving

${displaystyle c^{2}=(b+a)^{2}-2ab=b^{2}+2ab+a^{2}-2ab=a^{2}+b^{2}.}$

A similar proof uses four copies of a right triangle with sides a, b and c, arranged inside a square with side c as in the top half of the diagram.^[6] The triangles are similar with area ${tfrac {1}{2}}ab$ , while the small square has side b − a and area (b − a)². The area of the large square is therefore

${displaystyle (b-a)^{2}+4{frac {ab}{2}}=(b-a)^{2}+2ab=b^{2}-2ab+a^{2}+2ab=a^{2}+b^{2}.}$

But this is a square with side c and area c², so

${displaystyle c^{2}=a^{2}+b^{2}.}$

Other proofs of the theorem

This theorem may have more known proofs than any other (the law of quadratic reciprocity being another contender for that distinction); the book The Pythagorean Proposition contains 370 proofs.^[7]

Proof using similar triangles

This proof is based on the proportionality of the sides of three similar triangles, that is, upon the fact that the ratio of any two corresponding sides of similar triangles is the same regardless of the size of the triangles.

Let ABC represent a right triangle, with the right angle located at C, as shown on the figure. Draw the altitude from point C, and call H its intersection with the side AB. Point H divides the length of the hypotenuse c into parts d and e. The new triangle, ACH, is similar to triangle ABC, because they both have a right angle (by definition of the altitude), and they share the angle at A, meaning that the third angle will be the same in both triangles as well, marked as θ in the figure. By a similar reasoning, the triangle CBH is also similar to ABC. The proof of similarity of the triangles requires the triangle postulate: The sum of the angles in a triangle is two right angles, and is equivalent to the parallel postulate. Similarity of the triangles leads to the equality of ratios of corresponding sides:

${displaystyle {frac {BC}{AB}}={frac {BH}{BC}}{text{ and }}{frac {AC}{AB}}={frac {AH}{AC}}.}$

The first result equates the cosines of the angles θ, whereas the second result equates their sines.

These ratios can be written as

${displaystyle BC^{2}=ABtimes BH{text{ and }}AC^{2}=ABtimes AH.}$

Summing these two equalities results in

${displaystyle BC^{2}+AC^{2}=ABtimes BH+ABtimes AH=AB(AH+BH)=AB^{2},}$

which, after simplification, demonstrates the Pythagorean theorem:

${displaystyle BC^{2}+AC^{2}=AB^{2}.}$

The role of this proof in history is the subject of much speculation. The underlying question is why Euclid did not use this proof, but invented another. One conjecture is that the proof by similar triangles involved a theory of proportions, a topic not discussed until later in the Elements, and that the theory of proportions needed further development at that time.^[8]^[9]

Euclid’s proof

Proof in Euclid’s Elements

In outline, here is how the proof in Euclid’s Elements proceeds. The large square is divided into a left and right rectangle. A triangle is constructed that has half the area of the left rectangle. Then another triangle is constructed that has half the area of the square on the left-most side. These two triangles are shown to be congruent, proving this square has the same area as the left rectangle. This argument is followed by a similar version for the right rectangle and the remaining square. Putting the two rectangles together to reform the square on the hypotenuse, its area is the same as the sum of the area of the other two squares. The details follow.

Let A, B, C be the vertices of a right triangle, with a right angle at A. Drop a perpendicular from A to the side opposite the hypotenuse in the square on the hypotenuse. That line divides the square on the hypotenuse into two rectangles, each having the same area as one of the two squares on the legs.

For the formal proof, we require four elementary lemmata:

If two triangles have two sides of the one equal to two sides of the other, each to each, and the angles included by those sides equal, then the triangles are congruent (side-angle-side).
The area of a triangle is half the area of any parallelogram on the same base and having the same altitude.
The area of a rectangle is equal to the product of two adjacent sides.
The area of a square is equal to the product of two of its sides (follows from 3).

Next, each top square is related to a triangle congruent with another triangle related in turn to one of two rectangles making up the lower square.^[10]

Illustration including the new lines

Showing the two congruent triangles of half the area of rectangle BDLK and square BAGF

The proof is as follows:

Let ACB be a right-angled triangle with right angle CAB.
On each of the sides BC, AB, and CA, squares are drawn, CBDE, BAGF, and ACIH, in that order. The construction of squares requires the immediately preceding theorems in Euclid, and depends upon the parallel postulate.^[11]
From A, draw a line parallel to BD and CE. It will perpendicularly intersect BC and DE at K and L, respectively.
Join CF and AD, to form the triangles BCF and BDA.
Angles CAB and BAG are both right angles; therefore C, A, and G are collinear.
Angles CBD and FBA are both right angles; therefore angle ABD equals angle FBC, since both are the sum of a right angle and angle ABC.
Since AB is equal to FB, BD is equal to BC and angle ABD equals angle FBC, triangle ABD must be congruent to triangle FBC.
Since A-K-L is a straight line, parallel to BD, then rectangle BDLK has twice the area of triangle ABD because they share the base BD and have the same altitude BK, i.e., a line normal to their common base, connecting the parallel lines BD and AL. (lemma 2)
Since C is collinear with A and G, and this line is parallel to FB, then square BAGF must be twice in area to triangle FBC.
Therefore, rectangle BDLK must have the same area as square BAGF = AB².
By applying steps 3 to 10 to the other side of the figure, it can be similarly shown that rectangle CKLE must have the same area as square ACIH = AC².
Adding these two results, AB² + AC² = BD × BK + KL × KC
Since BD = KL, BD × BK + KL × KC = BD(BK + KC) = BD × BC
Therefore, AB² + AC² = BC², since CBDE is a square.

This proof, which appears in Euclid’s Elements as that of Proposition 47 in Book 1, demonstrates that the area of the square on the hypotenuse is the sum of the areas of the other two squares.^[12]^[13]
This is quite distinct from the proof by similarity of triangles, which is conjectured to be the proof that Pythagoras used.^[9]^[14]

Proofs by dissection and rearrangement

Another by rearrangement is given by the middle animation. A large square is formed with area c², from four identical right triangles with sides a, b and c, fitted around a small central square. Then two rectangles are formed with sides a and b by moving the triangles. Combining the smaller square with these rectangles produces two squares of areas a² and b², which must have the same area as the initial large square.^[15]

Diagram of the two algebraic proofs

The third, rightmost image also gives a proof. The upper two squares are divided as shown by the blue and green shading, into pieces that when rearranged can be made to fit in the lower square on the hypotenuse – or conversely the large square can be divided as shown into pieces that fill the other two. This way of cutting one figure into pieces and rearranging them to get another figure is called dissection. This shows the area of the large square equals that of the two smaller ones.^[16]

Animation showing proof by rearrangement of four identical right triangles

Animation showing another proof by rearrangement

Proof using an elaborate rearrangement

Einstein’s proof by dissection without rearrangement

Right triangle on the hypotenuse dissected into two similar right triangles on the legs, according to Einstein’s proof

Albert Einstein gave a proof by dissection in which the pieces do not need to be moved.^[17] Instead of using a square on the hypotenuse and two squares on the legs, one can use any other shape that includes the hypotenuse, and two similar shapes that each include one of two legs instead of the hypotenuse (see Similar figures on the three sides). In Einstein’s proof, the shape that includes the hypotenuse is the right triangle itself. The dissection consists of dropping a perpendicular from the vertex of the right angle of the triangle to the hypotenuse, thus splitting the whole triangle into two parts. Those two parts have the same shape as the original right triangle, and have the legs of the original triangle as their hypotenuses, and the sum of their areas is that of the original triangle. Because the ratio of the area of a right triangle to the square of its hypotenuse is the same for similar triangles, the relationship between the areas of the three triangles holds for the squares of the sides of the large triangle as well.

Proof by area-preserving shearing

Visual proof of the Pythagorean theorem by area-preserving shearing.

As shown in the accompanying animation, area-preserving shear mappings and translations can transform the squares on the sides adjacent to the right-angle onto the square on the hypotenuse, together covering it exactly.^[18] Each shear leaves the base and height unchanged, thus leaving the area unchanged too. The translations also leave the area unchanged, as they do not alter the shapes at all. Each square is first sheared into a parallelogram, and then into a rectangle which can be translated onto one section of the square on the hypotenuse.

Algebraic proofs

A related proof was published by future U.S. President James A. Garfield (then a U.S. Representative) (see diagram).^[19]^[20]^[21] Instead of a square it uses a trapezoid, which can be constructed from the square in the second of the above proofs by bisecting along a diagonal of the inner square, to give the trapezoid as shown in the diagram. The area of the trapezoid can be calculated to be half the area of the square, that is

${frac {1}{2}}(b+a)^{2}.$

The inner square is similarly halved, and there are only two triangles so the proof proceeds as above except for a factor of ${frac {1}{2}}$ , which is removed by multiplying by two to give the result.

Proof using differentials

One can arrive at the Pythagorean theorem by studying how changes in a side produce a change in the hypotenuse and employing calculus.^[22]^[23]^[24]

The triangle ABC is a right triangle, as shown in the upper part of the diagram, with BC the hypotenuse. At the same time the triangle lengths are measured as shown, with the hypotenuse of length y, the side AC of length x and the side AB of length a, as seen in the lower diagram part.

Diagram for differential proof

If x is increased by a small amount dx by extending the side AC slightly to D, then y also increases by dy. These form two sides of a triangle, CDE, which (with E chosen so CE is perpendicular to the hypotenuse) is a right triangle approximately similar to ABC. Therefore, the ratios of their sides must be the same, that is:

${displaystyle {frac {dy}{dx}}={frac {x}{y}}.}$

This can be rewritten as , which is a differential equation that can be solved by direct integration:

giving

${displaystyle y^{2}=x^{2}+C.}$

The constant can be deduced from x = 0, y = a to give the equation

${displaystyle y^{2}=x^{2}+a^{2}.}$

This is more of an intuitive proof than a formal one: it can be made more rigorous if proper limits are used in place of dx and dy.

Converse

The converse of the theorem is also true:^[25]

Given a triangle with sides of length a, b, and c, if a² + b² = c², then the angle between sides a and b is a right angle.

For any three positive real numbers a, b, and c such that a² + b² = c², there exists a triangle with sides a, b and c as a consequence of the converse of the triangle inequality.

This converse appears in Euclid’s Elements (Book I, Proposition 48): «If in a triangle the square on one of the sides equals the sum of the squares on the remaining two sides of the triangle, then the angle contained by the remaining two sides of the triangle is right.»^[26]

It can be proven using the law of cosines or as follows:

Let ABC be a triangle with side lengths a, b, and c, with a² + b² = c². Construct a second triangle with sides of length a and b containing a right angle. By the Pythagorean theorem, it follows that the hypotenuse of this triangle has length c = √a² + b², the same as the hypotenuse of the first triangle. Since both triangles’ sides are the same lengths a, b and c, the triangles are congruent and must have the same angles. Therefore, the angle between the side of lengths a and b in the original triangle is a right angle.

The above proof of the converse makes use of the Pythagorean theorem itself. The converse can also be proven without assuming the Pythagorean theorem.^[27]^[28]

A corollary of the Pythagorean theorem’s converse is a simple means of determining whether a triangle is right, obtuse, or acute, as follows. Let c be chosen to be the longest of the three sides and a + b > c (otherwise there is no triangle according to the triangle inequality). The following statements apply:^[29]

If a² + b² = c², then the triangle is right.
If a² + b² > c², then the triangle is acute.
If a² + b² < c², then the triangle is obtuse.

Edsger W. Dijkstra has stated this proposition about acute, right, and obtuse triangles in this language:

sgn(α + β − γ) = sgn(a² + b² − c²),

where α is the angle opposite to side a, β is the angle opposite to side b, γ is the angle opposite to side c, and sgn is the sign function.^[30]

Consequences and uses of the theorem

Pythagorean triples

A Pythagorean triple has three positive integers a, b, and c, such that a² + b² = c². In other words, a Pythagorean triple represents the lengths of the sides of a right triangle where all three sides have integer lengths.^[1] Such a triple is commonly written (a, b, c). Some well-known examples are (3, 4, 5) and (5, 12, 13).

A primitive Pythagorean triple is one in which a, b and c are coprime (the greatest common divisor of a, b and c is 1).

The following is a list of primitive Pythagorean triples with values less than 100:

(3, 4, 5), (5, 12, 13), (7, 24, 25), (8, 15, 17), (9, 40, 41), (11, 60, 61), (12, 35, 37), (13, 84, 85), (16, 63, 65), (20, 21, 29), (28, 45, 53), (33, 56, 65), (36, 77, 85), (39, 80, 89), (48, 55, 73), (65, 72, 97)

Inverse Pythagorean theorem

Given a right triangle with sides a,b,c and altitude (a line from the right angle and perpendicular to the hypotenuse ). The Pythagorean theorem has,

${displaystyle a^{2}+b^{2}=c^{2}}$

while the inverse Pythagorean theorem relates the two legs a,b to the altitude ,^[31]

${displaystyle {frac {1}{a^{2}}}+{frac {1}{b^{2}}}={frac {1}{d^{2}}}}$

The equation can be transformed to,

${displaystyle {frac {1}{(xz)^{2}}}+{frac {1}{(yz)^{2}}}={frac {1}{(xy)^{2}}}}$

where $x^{2}+y^{2}=z^{2}$ for any non-zero real x,y,z . If the are to be integers, the smallest solution is then

${displaystyle {frac {1}{20^{2}}}+{frac {1}{15^{2}}}={frac {1}{12^{2}}}}$

using the smallest Pythagorean triple . The reciprocal Pythagorean theorem is a special case of the optic equation

${displaystyle {frac {1}{p}}+{frac {1}{q}}={frac {1}{r}}}$

where the denominators are squares and also for a heptagonal triangle whose sides p,q,r are square numbers.

Incommensurable lengths

The spiral of Theodorus: A construction for line segments with lengths whose ratios are the square root of a positive integer

One of the consequences of the Pythagorean theorem is that line segments whose lengths are incommensurable (so the ratio of which is not a rational number) can be constructed using a straightedge and compass. Pythagoras’ theorem enables construction of incommensurable lengths because the hypotenuse of a triangle is related to the sides by the square root operation.

The figure on the right shows how to construct line segments whose lengths are in the ratio of the square root of any positive integer.^[32] Each triangle has a side (labeled «1») that is the chosen unit for measurement. In each right triangle, Pythagoras’ theorem establishes the length of the hypotenuse in terms of this unit. If a hypotenuse is related to the unit by the square root of a positive integer that is not a perfect square, it is a realization of a length incommensurable with the unit, such as √2, √3, √5 . For more detail, see Quadratic irrational.

Incommensurable lengths conflicted with the Pythagorean school’s concept of numbers as only whole numbers. The Pythagorean school dealt with proportions by comparison of integer multiples of a common subunit.^[33] According to one legend, Hippasus of Metapontum (ca. 470 B.C.) was drowned at sea for making known the existence of the irrational or incommensurable.^[34]^[35]

Complex numbers

The absolute value of a complex number z is the distance r from z to the origin

For any complex number

the absolute value or modulus is given by

${displaystyle r=|z|={sqrt {x^{2}+y^{2}}}.}$

So the three quantities, r, x and y are related by the Pythagorean equation,

${displaystyle r^{2}=x^{2}+y^{2}.}$

Note that r is defined to be a positive number or zero but x and y can be negative as well as positive. Geometrically r is the distance of the z from zero or the origin O in the complex plane.

This can be generalised to find the distance between two points, z₁ and z₂ say. The required distance is given by

${displaystyle |z_{1}-z_{2}|={sqrt {(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}},}$

so again they are related by a version of the Pythagorean equation,

${displaystyle |z_{1}-z_{2}|^{2}=(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}.}$

Euclidean distance

The distance formula in Cartesian coordinates is derived from the Pythagorean theorem.^[36] If (x₁, y₁) and (x₂, y₂) are points in the plane, then the distance between them, also called the Euclidean distance, is given by

${sqrt {(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}}}.$

More generally, in Euclidean n-space, the Euclidean distance between two points, $A,=,(a_{1},a_{2},dots ,a_{n})$ and $B,=,(b_{1},b_{2},dots ,b_{n})$ , is defined, by generalization of the Pythagorean theorem, as:

${sqrt {(a_{1}-b_{1})^{2}+(a_{2}-b_{2})^{2}+cdots +(a_{n}-b_{n})^{2}}}={sqrt {sum _{i=1}^{n}(a_{i}-b_{i})^{2}}}.$

If instead of Euclidean distance, the square of this value (the squared Euclidean distance, or SED) is used, the resulting equation avoids square roots and is simply a sum of the SED of the coordinates:

${displaystyle (a_{1}-b_{1})^{2}+(a_{2}-b_{2})^{2}+cdots +(a_{n}-b_{n})^{2}=sum _{i=1}^{n}(a_{i}-b_{i})^{2}.}$

The squared form is a smooth, convex function of both points, and is widely used in optimization theory and statistics, forming the basis of least squares.

Euclidean distance in other coordinate systems

If Cartesian coordinates are not used, for example, if polar coordinates are used in two dimensions or, in more general terms, if curvilinear coordinates are used, the formulas expressing the Euclidean distance are more complicated than the Pythagorean theorem, but can be derived from it. A typical example where the straight-line distance between two points is converted to curvilinear coordinates can be found in the applications of Legendre polynomials in physics. The formulas can be discovered by using Pythagoras’ theorem with the equations relating the curvilinear coordinates to Cartesian coordinates. For example, the polar coordinates (r, θ) can be introduced as:

{displaystyle x=rcos theta , y=rsin theta .}

Then two points with locations (r₁, θ₁) and (r₂, θ₂) are separated by a distance s:

${displaystyle s^{2}=(x_{1}-x_{2})^{2}+(y_{1}-y_{2})^{2}=(r_{1}cos theta _{1}-r_{2}cos theta _{2})^{2}+(r_{1}sin theta _{1}-r_{2}sin theta _{2})^{2}.}$

Performing the squares and combining terms, the Pythagorean formula for distance in Cartesian coordinates produces the separation in polar coordinates as:

${displaystyle {begin{aligned}s^{2}&=r_{1}^{2}+r_{2}^{2}-2r_{1}r_{2}left(cos theta _{1}cos theta _{2}+sin theta _{1}sin theta _{2}right)\&=r_{1}^{2}+r_{2}^{2}-2r_{1}r_{2}cos left(theta _{1}-theta _{2}right)\&=r_{1}^{2}+r_{2}^{2}-2r_{1}r_{2}cos Delta theta ,end{aligned}}}$

using the trigonometric product-to-sum formulas. This formula is the law of cosines, sometimes called the generalized Pythagorean theorem.^[37] From this result, for the case where the radii to the two locations are at right angles, the enclosed angle Δθ = π/2, and the form corresponding to Pythagoras’ theorem is regained: ${displaystyle s^{2}=r_{1}^{2}+r_{2}^{2}.}$ The Pythagorean theorem, valid for right triangles, therefore is a special case of the more general law of cosines, valid for arbitrary triangles.

Pythagorean trigonometric identity

Similar right triangles showing sine and cosine of angle θ

In a right triangle with sides a, b and hypotenuse c, trigonometry determines the sine and cosine of the angle θ between side a and the hypotenuse as:

$sin theta ={frac {b}{c}},quad cos theta ={frac {a}{c}}.$

From that it follows:

${cos }^{2}theta +{sin }^{2}theta ={frac {a^{2}+b^{2}}{c^{2}}}=1,$

where the last step applies Pythagoras’ theorem. This relation between sine and cosine is sometimes called the fundamental Pythagorean trigonometric identity.^[38] In similar triangles, the ratios of the sides are the same regardless of the size of the triangles, and depend upon the angles. Consequently, in the figure, the triangle with hypotenuse of unit size has opposite side of size sin θ and adjacent side of size cos θ in units of the hypotenuse.

Relation to the cross product

The area of a parallelogram as a cross product; vectors a and b identify a plane and a × b is normal to this plane.

The Pythagorean theorem relates the cross product and dot product in a similar way:^[39]

${displaystyle |mathbf {a} times mathbf {b} |^{2}+(mathbf {a} cdot mathbf {b} )^{2}=|mathbf {a} |^{2}|mathbf {b} |^{2}.}$

This can be seen from the definitions of the cross product and dot product, as

${begin{aligned}mathbf {a} times mathbf {b} &=abmathbf {n} sin {theta }\mathbf {a} cdot mathbf {b} &=abcos {theta },end{aligned}}$

with n a unit vector normal to both a and b. The relationship follows from these definitions and the Pythagorean trigonometric identity.

This can also be used to define the cross product. By rearranging the following equation is obtained

${displaystyle |mathbf {a} times mathbf {b} |^{2}=|mathbf {a} |^{2}|mathbf {b} |^{2}-(mathbf {a} cdot mathbf {b} )^{2}.}$

This can be considered as a condition on the cross product and so part of its definition, for example in seven dimensions.^[40]^[41]

Generalizations

Similar figures on the three sides

The Pythagorean theorem generalizes beyond the areas of squares on the three sides to any similar figures. This was known by Hippocrates of Chios in the 5th century BC,^[42] and was included by Euclid in his Elements:^[43]

If one erects similar figures (see Euclidean geometry) with corresponding sides on the sides of a right triangle, then the sum of the areas of the ones on the two smaller sides equals the area of the one on the larger side.

This extension assumes that the sides of the original triangle are the corresponding sides of the three congruent figures (so the common ratios of sides between the similar figures are a:b:c).^[44] While Euclid’s proof only applied to convex polygons, the theorem also applies to concave polygons and even to similar figures that have curved boundaries (but still with part of a figure’s boundary being the side of the original triangle).^[44]

The basic idea behind this generalization is that the area of a plane figure is proportional to the square of any linear dimension, and in particular is proportional to the square of the length of any side. Thus, if similar figures with areas A, B and C are erected on sides with corresponding lengths a, b and c then:

${frac {A}{a^{2}}}={frac {B}{b^{2}}}={frac {C}{c^{2}}},,$

$Rightarrow A+B={frac {a^{2}}{c^{2}}}C+{frac {b^{2}}{c^{2}}}C,.$

But, by the Pythagorean theorem, a² + b² = c², so A + B = C.

Conversely, if we can prove that A + B = C for three similar figures without using the Pythagorean theorem, then we can work backwards to construct a proof of the theorem. For example, the starting center triangle can be replicated and used as a triangle C on its hypotenuse, and two similar right triangles (A and B ) constructed on the other two sides, formed by dividing the central triangle by its altitude. The sum of the areas of the two smaller triangles therefore is that of the third, thus A + B = C and reversing the above logic leads to the Pythagorean theorem a² + b² = c². (See also Einstein’s proof by dissection without rearrangement)

Generalization for similar triangles,
green area A + B = blue area C

Pythagoras’ theorem using similar right triangles

Generalization for regular pentagons

Law of cosines

The Pythagorean theorem is a special case of the more general theorem relating the lengths of sides in any triangle, the law of cosines:^[45]

${displaystyle a^{2}+b^{2}-2abcos {theta }=c^{2},}$

where theta is the angle between sides and .

When theta is ${frac {pi }{2}}$ radians or 90°, then , and the formula reduces to the usual Pythagorean theorem.

Arbitrary triangle

Generalization of Pythagoras’ theorem by Tâbit ibn Qorra.^[46] Lower panel: reflection of triangle CAD (top) to form triangle DAC, similar to triangle ABC (top).

At any selected angle of a general triangle of sides a, b, c, inscribe an isosceles triangle such that the equal angles at its base θ are the same as the selected angle. Suppose the selected angle θ is opposite the side labeled c. Inscribing the isosceles triangle forms triangle CAD with angle θ opposite side b and with side r along c. A second triangle is formed with angle θ opposite side a and a side with length s along c, as shown in the figure. Thābit ibn Qurra stated that the sides of the three triangles were related as:^[47]^[48]

$a^{2}+b^{2}=c(r+s) .$

As the angle θ approaches π/2, the base of the isosceles triangle narrows, and lengths r and s overlap less and less. When θ = π/2, ADB becomes a right triangle, r + s = c, and the original Pythagorean theorem is regained.

One proof observes that triangle ABC has the same angles as triangle CAD, but in opposite order. (The two triangles share the angle at vertex A, both contain the angle θ, and so also have the same third angle by the triangle postulate.) Consequently, ABC is similar to the reflection of CAD, the triangle DAC in the lower panel. Taking the ratio of sides opposite and adjacent to θ,

${displaystyle {frac {c}{b}}={frac {b}{r}} .}$

Likewise, for the reflection of the other triangle,

${displaystyle {frac {c}{a}}={frac {a}{s}} .}$

Clearing fractions and adding these two relations:

${displaystyle cs+cr=a^{2}+b^{2} ,}$

the required result.

The theorem remains valid if the angle theta is obtuse so the lengths r and s are non-overlapping.

General triangles using parallelograms

Generalization for arbitrary triangles,
green area = blue area

Construction for proof of parallelogram generalization

Pappus’s area theorem is a further generalization, that applies to triangles that are not right triangles, using parallelograms on the three sides in place of squares (squares are a special case, of course). The upper figure shows that for a scalene triangle, the area of the parallelogram on the longest side is the sum of the areas of the parallelograms on the other two sides, provided the parallelogram on the long side is constructed as indicated (the dimensions labeled with arrows are the same, and determine the sides of the bottom parallelogram). This replacement of squares with parallelograms bears a clear resemblance to the original Pythagoras’ theorem, and was considered a generalization by Pappus of Alexandria in 4 AD^[49]^[50]

The lower figure shows the elements of the proof. Focus on the left side of the figure. The left green parallelogram has the same area as the left, blue portion of the bottom parallelogram because both have the same base b and height h. However, the left green parallelogram also has the same area as the left green parallelogram of the upper figure, because they have the same base (the upper left side of the triangle) and the same height normal to that side of the triangle. Repeating the argument for the right side of the figure, the bottom parallelogram has the same area as the sum of the two green parallelograms.

Solid geometry

Pythagoras’ theorem in three dimensions relates the diagonal AD to the three sides.

A tetrahedron with outward facing right-angle corner

In terms of solid geometry, Pythagoras’ theorem can be applied to three dimensions as follows. Consider a rectangular solid as shown in the figure. The length of diagonal BD is found from Pythagoras’ theorem as:

${overline {BD}}^{,2}={overline {BC}}^{,2}+{overline {CD}}^{,2} ,$

where these three sides form a right triangle. Using horizontal diagonal BD and the vertical edge AB, the length of diagonal AD then is found by a second application of Pythagoras’ theorem as:

${overline {AD}}^{,2}={overline {AB}}^{,2}+{overline {BD}}^{,2} ,$

or, doing it all in one step:

${overline {AD}}^{,2}={overline {AB}}^{,2}+{overline {BC}}^{,2}+{overline {CD}}^{,2} .$

This result is the three-dimensional expression for the magnitude of a vector v (the diagonal AD) in terms of its orthogonal components {v_k} (the three mutually perpendicular sides):

$|mathbf {v} |^{2}=sum _{k=1}^{3}|mathbf {v} _{k}|^{2}.$

This one-step formulation may be viewed as a generalization of Pythagoras’ theorem to higher dimensions. However, this result is really just the repeated application of the original Pythagoras’ theorem to a succession of right triangles in a sequence of orthogonal planes.

A substantial generalization of the Pythagorean theorem to three dimensions is de Gua’s theorem, named for Jean Paul de Gua de Malves: If a tetrahedron has a right angle corner (like a corner of a cube), then the square of the area of the face opposite the right angle corner is the sum of the squares of the areas of the other three faces. This result can be generalized as in the «n-dimensional Pythagorean theorem»:^[51]

Let ${displaystyle x_{1},x_{2},ldots ,x_{n}}$ be orthogonal vectors in Rⁿ. Consider the n-dimensional simplex S with vertices ${displaystyle 0,x_{1},ldots ,x_{n}}$ . (Think of the (n − 1)-dimensional simplex with vertices $x_{1},ldots ,x_{n}$ not including the origin as the «hypotenuse» of S and the remaining (n − 1)-dimensional faces of S as its «legs».) Then the square of the volume of the hypotenuse of S is the sum of the squares of the volumes of the n legs.

This statement is illustrated in three dimensions by the tetrahedron in the figure. The «hypotenuse» is the base of the tetrahedron at the back of the figure, and the «legs» are the three sides emanating from the vertex in the foreground. As the depth of the base from the vertex increases, the area of the «legs» increases, while that of the base is fixed. The theorem suggests that when this depth is at the value creating a right vertex, the generalization of Pythagoras’ theorem applies. In a different wording:^[52]

Given an n-rectangular n-dimensional simplex, the square of the (n − 1)-content of the facet opposing the right vertex will equal the sum of the squares of the (n − 1)-contents of the remaining facets.

Inner product spaces

Vectors involved in the parallelogram law

The Pythagorean theorem can be generalized to inner product spaces,^[53] which are generalizations of the familiar 2-dimensional and 3-dimensional Euclidean spaces. For example, a function may be considered as a vector with infinitely many components in an inner product space, as in functional analysis.^[54]

In an inner product space, the concept of perpendicularity is replaced by the concept of orthogonality: two vectors v and w are orthogonal if their inner product is zero. The inner product is a generalization of the dot product of vectors. The dot product is called the standard inner product or the Euclidean inner product. However, other inner products are possible.^[55]

The concept of length is replaced by the concept of the norm ||v|| of a vector v, defined as:^[56]

lVert mathbf {v} rVert equiv {sqrt {langle mathbf {v} ,mathbf {v} rangle }},.

In an inner-product space, the Pythagorean theorem states that for any two orthogonal vectors v and w we have

$left|mathbf {v} +mathbf {w} right|^{2}=left|mathbf {v} right|^{2}+left|mathbf {w} right|^{2}.$

Here the vectors v and w are akin to the sides of a right triangle with hypotenuse given by the vector sum v + w. This form of the Pythagorean theorem is a consequence of the properties of the inner product:

${displaystyle {begin{aligned}left|mathbf {v} +mathbf {w} right|^{2}&=langle mathbf {v+w} , mathbf {v+w} rangle \[3mu]&=langle mathbf {v} , mathbf {v} rangle +langle mathbf {w} , mathbf {w} rangle +langle mathbf {v, w} rangle +langle mathbf {w, v} rangle \[3mu]&=left|mathbf {v} right|^{2}+left|mathbf {w} right|^{2},end{aligned}}}$

where because of orthogonality.

A further generalization of the Pythagorean theorem in an inner product space to non-orthogonal vectors is the parallelogram law :^[56]

$2|mathbf {v} |^{2}+2|mathbf {w} |^{2}=|mathbf {v+w} |^{2}+|mathbf {v-w} |^{2} ,$

which says that twice the sum of the squares of the lengths of the sides of a parallelogram is the sum of the squares of the lengths of the diagonals. Any norm that satisfies this equality is ipso facto a norm corresponding to an inner product.^[56]

The Pythagorean identity can be extended to sums of more than two orthogonal vectors. If v₁, v₂, …, v_n are pairwise-orthogonal vectors in an inner-product space, then application of the Pythagorean theorem to successive pairs of these vectors (as described for 3-dimensions in the section on solid geometry) results in the equation^[57]

${displaystyle left|sum _{k=1}^{n}mathbf {v} _{k}right|^{2}=sum _{k=1}^{n}|mathbf {v} _{k}|^{2}}$

Sets of m-dimensional objects in n-dimensional space

Another generalization of the Pythagorean theorem applies to Lebesgue-measurable sets of objects in any number of dimensions. Specifically, the square of the measure of an m-dimensional set of objects in one or more parallel m-dimensional flats in n-dimensional Euclidean space is equal to the sum of the squares of the measures of the orthogonal projections of the object(s) onto all m-dimensional coordinate subspaces.^[58]

In mathematical terms:

$mu _{ms}^{2}=sum _{i=1}^{x}mathbf {mu ^{2}} _{mp_{i}}$

where:

Non-Euclidean geometry

The Pythagorean theorem is derived from the axioms of Euclidean geometry, and in fact, were the Pythagorean theorem to fail for some right triangle, then the plane in which this triangle is contained cannot be Euclidean. More precisely, the Pythagorean theorem implies, and is implied by, Euclid’s Parallel (Fifth) Postulate.^[59]^[60] Thus, right triangles in a non-Euclidean geometry^[61]
do not satisfy the Pythagorean theorem. For example, in spherical geometry, all three sides of the right triangle (say a, b, and c) bounding an octant of the unit sphere have length equal to π/2, and all its angles are right angles, which violates the Pythagorean theorem because
${displaystyle a^{2}+b^{2}=2c^{2}>c^{2}}$ .

Here two cases of non-Euclidean geometry are considered—spherical geometry and hyperbolic plane geometry; in each case, as in the Euclidean case for non-right triangles, the result replacing the Pythagorean theorem follows from the appropriate law of cosines.

However, the Pythagorean theorem remains true in hyperbolic geometry and elliptic geometry if the condition that the triangle be right is replaced with the condition that two of the angles sum to the third, say A+B = C. The sides are then related as follows: the sum of the areas of the circles with diameters a and b equals the area of the circle with diameter c.^[62]

Spherical geometry

For any right triangle on a sphere of radius R (for example, if γ in the figure is a right angle), with sides a, b, c, the relation between the sides takes the form:^[63]

${displaystyle cos left({frac {c}{R}}right)=cos left({frac {a}{R}}right)cos left({frac {b}{R}}right).}$

This equation can be derived as a special case of the spherical law of cosines that applies to all spherical triangles:

$cos left({frac {c}{R}}right)=cos left({frac {a}{R}}right)cos left({frac {b}{R}}right)+sin left({frac {a}{R}}right)sin left({frac {b}{R}}right)cos gamma .$

By expressing the Maclaurin series for the cosine function as an asymptotic expansion with the remainder term in big O notation,

$cos x=1-{frac {x^{2}}{2}}+O(x^{4}){text{ as }}xto 0 ,$

it can be shown that as the radius R approaches infinity and the arguments a/R, b/R, and c/R tend to zero, the spherical relation between the sides of a right triangle approaches the Euclidean form of the Pythagorean theorem. Substituting the asymptotic expansion for each of the cosines into the spherical relation for a right triangle yields

$1-{frac {1}{2}}left({frac {c}{R}}right)^{2}+Oleft({frac {1}{R^{4}}}right)=left[1-{frac {1}{2}}left({frac {a}{R}}right)^{2}+Oleft({frac {1}{R^{4}}}right)right]left[1-{frac {1}{2}}left({frac {b}{R}}right)^{2}+Oleft({frac {1}{R^{4}}}right)right]{text{ as }}Rto infty .$

The constants a⁴, b⁴, and c⁴ have been absorbed into the big O remainder terms since they are independent of the radius R. This asymptotic relationship can be further simplified by multiplying out the bracketed quantities, cancelling the ones, multiplying through by −2, and collecting all the error terms together:

$left({frac {c}{R}}right)^{2}=left({frac {a}{R}}right)^{2}+left({frac {b}{R}}right)^{2}+Oleft({frac {1}{R^{4}}}right){text{ as }}Rto infty .$

After multiplying through by R², the Euclidean Pythagorean relationship c² = a² + b² is recovered in the limit as the radius R approaches infinity (since the remainder term tends to zero):

$c^{2}=a^{2}+b^{2}+Oleft({frac {1}{R^{2}}}right){text{ as }}Rto infty .$

For small right triangles (a, b << R), the cosines can be eliminated to avoid loss of significance, giving

${displaystyle sin ^{2}{frac {c}{2R}}=sin ^{2}{frac {a}{2R}}+sin ^{2}{frac {b}{2R}}-2sin ^{2}{frac {a}{2R}}sin ^{2}{frac {b}{2R}},.}$

Hyperbolic geometry

In a hyperbolic space with uniform Gaussian curvature −1/R², for a right triangle with legs a, b, and hypotenuse c, the relation between the sides takes the form:^[64]

${displaystyle cosh {frac {c}{R}}=cosh {frac {a}{R}},cosh {frac {b}{R}}}$

where cosh is the hyperbolic cosine. This formula is a special form of the hyperbolic law of cosines that applies to all hyperbolic triangles:^[65]

${displaystyle cosh {frac {c}{R}}=cosh {frac {a}{R}} cosh {frac {b}{R}}-sinh {frac {a}{R}} sinh {frac {b}{R}} cos gamma ,}$

with γ the angle at the vertex opposite the side c.

By using the Maclaurin series for the hyperbolic cosine, cosh x ≈ 1 + x²/2, it can be shown that as a hyperbolic triangle becomes very small (that is, as a, b, and c all approach zero), the hyperbolic relation for a right triangle approaches the form of Pythagoras’ theorem.

For small right triangles (a, b << R), the hyperbolic cosines can be eliminated to avoid loss of significance, giving

${displaystyle sinh ^{2}{frac {c}{2R}}=sinh ^{2}{frac {a}{2R}}+sinh ^{2}{frac {b}{2R}}+2sinh ^{2}{frac {a}{2R}}sinh ^{2}{frac {b}{2R}},.}$

Very small triangles

For any uniform curvature K (positive, zero, or negative), in very small right triangles (|K|a², |K|b² << 1) with hypotenuse c, it can be shown that

${displaystyle c^{2}=a^{2}+b^{2}-{frac {K}{3}}a^{2}b^{2}-{frac {K^{2}}{45}}a^{2}b^{2}(a^{2}+b^{2})-{frac {2K^{3}}{945}}a^{2}b^{2}(a^{2}-b^{2})^{2}+O(K^{4}c^{10}),.}$

Differential geometry

The Pythagorean theorem applies to infinitesimal triangles seen in differential geometry. In three dimensional space, the distance between two infinitesimally separated points satisfies

${displaystyle ds^{2}=dx^{2}+dy^{2}+dz^{2},}$

with ds the element of distance and (dx, dy, dz) the components of the vector separating the two points. Such a space is called a Euclidean space. However, in Riemannian geometry, a generalization of this expression useful for general coordinates (not just Cartesian) and general spaces (not just Euclidean) takes the form:^[66]

$ds^{2}=sum _{i,j}^{n}g_{ij},dx_{i},dx_{j}$

which is called the metric tensor. (Sometimes, by abuse of language, the same term is applied to the set of coefficients g_ij.) It may be a function of position, and often describes curved space. A simple example is Euclidean (flat) space expressed in curvilinear coordinates. For example, in polar coordinates:

$ds^{2}=dr^{2}+r^{2}dtheta ^{2} .$

History

There is debate whether the Pythagorean theorem was discovered once, or many times in many places, and the date of first discovery is uncertain, as is the date of the first proof. Historians of Mesopotamian mathematics have concluded that the Pythagorean rule was in widespread use during the Old Babylonian period (20th to 16th centuries BC), over a thousand years before Pythagoras was born.^[68]^[69]^[70]^[71] The history of the theorem can be divided into four parts: knowledge of Pythagorean triples, knowledge of the relationship among the sides of a right triangle, knowledge of the relationships among adjacent angles, and proofs of the theorem within some deductive system.

Written between 2000 and 1786 BC, the Egyptian Middle Kingdom Berlin Papyrus 6619 includes a problem whose solution is the Pythagorean triple 6:8:10, but the problem does not mention a triangle. The Mesopotamian tablet Plimpton 322, written between 1790 and 1750 BC during the reign of King Hammurabi the Great, contains many entries closely related to Pythagorean triples.

In India, the Baudhayana Shulba Sutra, the dates of which are given variously as between the 8th and 5th century BC,^[72] contains a list of Pythagorean triples and a statement of the Pythagorean theorem, both in the special case of the isosceles right triangle and in the general case, as does the Apastamba Shulba Sutra (c. 600 BC).^[a]

Byzantine Neoplatonic philosopher and mathematician Proclus, writing in the fifth century AD, states two arithmetic rules, «one of them attributed to Plato, the other to Pythagoras»,^[74] for generating special Pythagorean triples. The rule attributed to Pythagoras (c. 570 – c. 495 BC) starts from an odd number and produces a triple with leg and hypotenuse differing by one unit; the rule attributed to Plato (428/427 or 424/423 – 348/347 BC) starts from an even number and produces a triple with leg and hypotenuse differing by two units. According to Thomas L. Heath (1861–1940), no specific attribution of the theorem to Pythagoras exists in the surviving Greek literature from the five centuries after Pythagoras lived.^[75] However, when authors such as Plutarch and Cicero attributed the theorem to Pythagoras, they did so in a way which suggests that the attribution was widely known and undoubted.^[76]^[77] Classicist Kurt von Fritz wrote, «Whether this formula is rightly attributed to Pythagoras personally, but one can safely assume that it belongs to the very oldest period of Pythagorean mathematics.»^[35] Around 300 BC, in Euclid’s Elements, the oldest extant axiomatic proof of the theorem is presented.^[78]

With contents known much earlier, but in surviving texts dating from roughly the 1st century BC, the Chinese text Zhoubi Suanjing (周髀算经), (The Arithmetical Classic of the Gnomon and the Circular Paths of Heaven) gives a reasoning for the Pythagorean theorem for the (3, 4, 5) triangle — in China it is called the «Gougu theorem» (勾股定理).^[79]^[80] During the Han Dynasty (202 BC to 220 AD), Pythagorean triples appear in The Nine Chapters on the Mathematical Art,^[81] together with a mention of right triangles.^[82] Some believe the theorem arose first in China,^[83] where it is alternatively known as the «Shang Gao theorem» (商高定理),^[84] named after the Duke of Zhou’s astronomer and mathematician, whose reasoning composed most of what was in the Zhoubi Suanjing.^[85]

Notes and references

Notes

^ Van der Waerden believed that this material «was certainly based on earlier traditions». Carl Boyer states that the Pythagorean theorem in the Śulba-sũtram may have been influenced by ancient Mesopotamian math, but there is no conclusive evidence in favor or opposition of this possibility.^[73]

References

^ ^a ^b Judith D. Sally; Paul Sally (2007). «Chapter 3: Pythagorean triples». Roots to research: a vertical development of mathematical problems. American Mathematical Society Bookstore. p. 63. ISBN 978-0-8218-4403-8.
^ Benson, Donald. The Moment of Proof : Mathematical Epiphanies, pp. 172–173 (Oxford University Press, 1999).
^ Euclid (1956), pp. 351–352
^ Huffman, Carl (23 February 2005). «Pythagoras». In Zalta, Edward N. (ed.). The Stanford Encyclopedia of Philosophy (Winter 2018 Edition)., «It should now be clear that decisions about sources are crucial in addressing the question of whether Pythagoras was a mathematician and scientist. The view of Pythagoras’s cosmos sketched in the first five paragraphs of this section, according to which he was neither a mathematician nor a scientist, remains the consensus.»
^ Alexander Bogomolny. «Cut-the-knot.org: Pythagorean theorem and its many proofs, Proof #4». Cut the Knot. Retrieved 4 November 2010.
^
Alexander Bogomolny. «Cut-the-knot.org: Pythagorean theorem and its many proofs, Proof #3». Cut the Knot. Retrieved 4 November 2010.
^ (Loomis 1968)
^ (Maor 2007, p. 39)
^ ^a ^b
Stephen W. Hawking (2005). God created the integers: the mathematical breakthroughs that changed history. Philadelphia: Running Press Book Publishers. p. 12. ISBN 0-7624-1922-9.

This proof first appeared after a computer program was set to check Euclidean proofs.
^ See for example Pythagorean theorem by shear mapping Archived 2016-10-14 at the Wayback Machine, Saint Louis University website Java applet
^
Jan Gullberg (1997). Mathematics: from the birth of numbers. W. W. Norton & Company. p. 435. ISBN 0-393-04002-X.
^ Heiberg, J.L. «Euclid’s Elements of Geometry» (PDF). pp. 46–47.
^ «Euclid’s Elements, Book I, Proposition 47». web page version using Java applets from Euclid’s Elements by Prof. David E. Joyce, Clark University
^ The proof by Pythagoras probably was not a general one, as the theory of proportions was developed only two centuries after Pythagoras; see (Maor 2007, p. 25)
^ Alexander Bogomolny. «Pythagorean theorem, proof number 10». Cut the Knot. Retrieved 27 February 2010.
^ (Loomis 1968, p. 113, Geometric proof 22 and Figure 123)
^ Schroeder, Manfred Robert (2012). Fractals, Chaos, Power Laws: Minutes from an Infinite Paradise. Courier Corporation. pp. 3–4. ISBN 978-0486134789.
^ Polster, Burkard (2004). Q.E.D.: Beauty in Mathematical Proof. Walker Publishing Company. p. 49.
^
Published in a weekly mathematics column: James A Garfield (1876). «Pons Asinorum». The New England Journal of Education. 3 (14): 161. as noted in William Dunham (1997). The mathematical universe: An alphabetical journey through the great proofs, problems, and personalities. Wiley. p. 96. ISBN 0-471-17661-3. and in A calendar of mathematical dates: April 1, 1876 Archived July 14, 2010, at the Wayback Machine by V. Frederick Rickey
^ Lantz, David. «Garfield’s proof of the Pythagorean Theorem». Math.Colgate.edu. Archived from the original on 2013-08-28. Retrieved 2018-01-14.
^ Maor, Eli, The Pythagorean Theorem, Princeton University Press, 2007: pp. 106-107.
^
Mike Staring (1996). «The Pythagorean proposition: A proof by means of calculus». Mathematics Magazine. Mathematical Association of America. 69 (1): 45–46. doi:10.2307/2691395. JSTOR 2691395.
^
Bogomolny, Alexander. «Pythagorean Theorem». Interactive Mathematics Miscellany and Puzzles. Alexander Bogomolny. Archived from the original on 2010-07-06. Retrieved 2010-05-09.
^
Bruce C. Berndt (1988). «Ramanujan – 100 years old (fashioned) or 100 years new (fangled)?». The Mathematical Intelligencer. 10 (3): 24–31. doi:10.1007/BF03026638. S2CID 123311054.
^
Judith D. Sally; Paul J. Sally Jr. (2007-12-21). «Theorem 2.4 (Converse of the Pythagorean theorem).». Roots to Research. American Mathematical Society. pp. 54–55. ISBN 978-0-8218-4403-8.
^
Euclid’s Elements, Book I, Proposition 48 From D.E. Joyce’s web page at Clark University
^ Casey, Stephen, «The converse of the theorem of Pythagoras», Mathematical Gazette 92, July 2008, 309–313.
^ Mitchell, Douglas W., «Feedback on 92.47», Mathematical Gazette 93, March 2009, 156.
^
Ernest Julius Wilczynski; Herbert Ellsworth Slaught (1914). «Theorem 1 and Theorem 2». Plane trigonometry and applications. Allyn and Bacon. p. 85.
^ Dijkstra, Edsger W. (September 7, 1986). «On the theorem of Pythagoras». EWD975. E. W. Dijkstra Archive.
^ Alexander Bogomolny, Pythagorean Theorem for the Reciprocals,https://www.cut-the-knot.org/pythagoras/PTForReciprocals.shtml
^ Law, Henry (1853). «Corollary 5 of Proposition XLVII (Pythagoras’s Theorem)». The Elements of Euclid: with many additional propositions, and explanatory notes, to which is prefixed an introductory essay on logic. John Weale. p. 49.
^
Shaughan Lavine (1994). Understanding the infinite. Harvard University Press. p. 13. ISBN 0-674-92096-1.
^
(Heath 1921, Vol I, pp. 65); Hippasus was on a voyage at the time, and his fellows cast him overboard. See James R. Choike (1980). «The pentagram and the discovery of an irrational number». The College Mathematics Journal. 11: 312–316.
^ ^a ^b
A careful discussion of Hippasus’s contributions is found in
Kurt Von Fritz (Apr 1945). «The Discovery of Incommensurability by Hippasus of Metapontum». Annals of Mathematics. Second Series. 46 (2): 242–264. doi:10.2307/1969021. JSTOR 1969021.
^ Jon Orwant; Jarkko Hietaniemi; John Macdonald (1999). «Euclidean distance». Mastering algorithms with Perl. O’Reilly Media, Inc. p. 426. ISBN 1-56592-398-7.
^ Wentworth, George (2009). Plane Trigonometry and Tables. BiblioBazaar, LLC. p. 116. ISBN 978-1-103-07998-8., Exercises, page 116
^
Lawrence S. Leff (2005). PreCalculus the Easy Way (7th ed.). Barron’s Educational Series. p. 296. ISBN 0-7641-2892-2.
^
WS Massey (Dec 1983). «Cross products of vectors in higher-dimensional Euclidean spaces» (PDF). The American Mathematical Monthly. Mathematical Association of America. 90 (10): 697–701. doi:10.2307/2323537. JSTOR 2323537. S2CID 43318100. Archived from the original (PDF) on 2021-02-26.
^ Pertti Lounesto (2001). «§7.4 Cross product of two vectors». Clifford algebras and spinors (2nd ed.). Cambridge University Press. p. 96. ISBN 0-521-00551-5.
^
Francis Begnaud Hildebrand (1992). Methods of applied mathematics (Reprint of Prentice-Hall 1965 2nd ed.). Courier Dover Publications. p. 24. ISBN 0-486-67002-3.
^ Heath, T. L., A History of Greek Mathematics, Oxford University Press, 1921; reprinted by Dover, 1981.
^ Euclid’s Elements: Book VI, Proposition VI 31: «In right-angled triangles the figure on the side subtending the right angle is equal to the similar and similarly described figures on the sides containing the right angle.»
^ ^a ^b Putz, John F. and Sipka, Timothy A. «On generalizing the Pythagorean theorem», The College Mathematics Journal 34 (4), September 2003, pp. 291–295.
^
Lawrence S. Leff (2005-05-01). cited work. Barron’s Educational Series. p. 326. ISBN 0-7641-2892-2.
^
Howard Whitley Eves (1983). «§4.8:…generalization of Pythagorean theorem». Great moments in mathematics (before 1650). Mathematical Association of America. p. 41. ISBN 0-88385-310-8.
^
Aydin Sayili (Mar 1960). «Thâbit ibn Qurra’s Generalization of the Pythagorean Theorem». Isis. 51 (1): 35–37. doi:10.1086/348837. JSTOR 227603. S2CID 119868978.
^
Judith D. Sally; Paul Sally (2007-12-21). «Exercise 2.10 (ii)». Roots to Research: A Vertical Development of Mathematical Problems. p. 62. ISBN 978-0-8218-4403-8.
^ For the details of such a construction, see Jennings, George (1997). «Figure 1.32: The generalized Pythagorean theorem». Modern geometry with applications: with 150 figures (3rd ed.). Springer. p. 23. ISBN 0-387-94222-X.
^ Claudi Alsina, Roger B. Nelsen: Charming Proofs: A Journey Into Elegant Mathematics. MAA, 2010, ISBN 9780883853481, pp. 77–78 (excerpt, p. 77, at Google Books)
^
Rajendra Bhatia (1997). Matrix analysis. Springer. p. 21. ISBN 0-387-94846-5.
^
For an extended discussion of this generalization, see, for example, Willie W. Wong Archived 2009-12-29 at the Wayback Machine 2002, A generalized n-dimensional Pythagorean theorem.
^
Ferdinand van der Heijden; Dick de Ridder (2004). Classification, parameter estimation, and state estimation. Wiley. p. 357. ISBN 0-470-09013-8.
^
Qun Lin; Jiafu Lin (2006). Finite element methods: accuracy and improvement. Elsevier. p. 23. ISBN 7-03-016656-6.
^
Howard Anton; Chris Rorres (2010). Elementary Linear Algebra: Applications Version (10th ed.). Wiley. p. 336. ISBN 978-0-470-43205-1.
^ ^a ^b ^c
Karen Saxe (2002). «Theorem 1.2». Beginning functional analysis. Springer. p. 7. ISBN 0-387-95224-1.
^ Douglas, Ronald G. (1998). Banach Algebra Techniques in Operator Theory (2nd ed.). New York, New York: Springer-Verlag New York, Inc. pp. 60–61. ISBN 978-0-387-98377-6.
^
Donald R Conant & William A Beyer (Mar 1974). «Generalized Pythagorean Theorem». The American Mathematical Monthly. Mathematical Association of America. 81 (3): 262–265. doi:10.2307/2319528. JSTOR 2319528.
^
Eric W. Weisstein (2003). CRC concise encyclopedia of mathematics (2nd ed.). p. 2147. ISBN 1-58488-347-2. The parallel postulate is equivalent to the Equidistance postulate, Playfair axiom, Proclus axiom, the Triangle postulate and the Pythagorean theorem.
^
Alexander R. Pruss (2006). The principle of sufficient reason: a reassessment. Cambridge University Press. p. 11. ISBN 0-521-85959-X. We could include…the parallel postulate and derive the Pythagorean theorem. Or we could instead make the Pythagorean theorem among the other axioms and derive the parallel postulate.
^
Stephen W. Hawking (2005). cited work. p. 4. ISBN 0-7624-1922-9.
^
Victor Pambuccian (December 2010). «Maria Teresa Calapso’s Hyperbolic Pythagorean Theorem». The Mathematical Intelligencer. 32 (4): 2. doi:10.1007/s00283-010-9169-0.
^
Barrett O’Neill (2006). «Exercise 4». Elementary differential geometry (2nd ed.). Academic Press. p. 441. ISBN 0-12-088735-5.
^
Saul Stahl (1993). «Theorem 8.3». The Poincaré half-plane: a gateway to modern geometry. Jones & Bartlett Learning. p. 122. ISBN 0-86720-298-X.
^
Jane Gilman (1995). «Hyperbolic triangles». Two-generator discrete subgroups of PSL(2,R). American Mathematical Society Bookstore. ISBN 0-8218-0361-1.
^
Tai L. Chow (2000). Mathematical methods for physicists: a concise introduction. Cambridge University Press. p. 52. ISBN 0-521-65544-7.
^ Neugebauer 1969, p. 36.
^ Neugebauer 1969: p. 36 «In other words it was known during the whole duration of Babylonian mathematics that the sum of the squares on the lengths of the sides of a right triangle equals the square of the length of the hypotenuse.»
^ Friberg, Jöran (1981). «Methods and traditions of Babylonian mathematics: Plimpton 322, Pythagorean triples, and the Babylonian triangle parameter equations». Historia Mathematica. 8: 277–318. doi:10.1016/0315-0860(81)90069-0.: p. 306 «Although Plimpton 322 is a unique text of its kind, there are several other known texts testifying that the Pythagorean theorem was well known to the mathematicians of the Old Babylonian period.»
^ Høyrup, Jens. «Pythagorean ‘Rule’ and ‘Theorem’ – Mirror of the Relation Between Babylonian and Greek Mathematics». In Renger, Johannes (ed.). Babylon: Focus mesopotamischer Geschichte, Wiege früher Gelehrsamkeit, Mythos in der Moderne. 2. Internationales Colloquium der Deutschen Orient-Gesellschaft 24.–26. März 1998 in Berlin (PDF). Berlin: Deutsche Orient-Gesellschaft / Saarbrücken: SDV Saarbrücker Druckerei und Verlag. pp. 393–407., p. 406, «To judge from this evidence alone it is therefore likely that the Pythagorean rule was discovered within the lay surveyors’ environment, possibly as a spin-off from the problem treated in Db₂-146, somewhere between 2300 and 1825 BC.» (Db₂-146 is an Old Babylonian clay tablet from Eshnunna concerning the computation of the sides of a rectangle given its area and diagonal.)
^ Robson, E. (2008). Mathematics in Ancient Iraq: A Social History. Princeton University Press.: p. 109 «Many Old Babylonian mathematical practitioners … knew that the square on the diagonal of a right triangle had the same area as the sum of the squares on the length and width: that relationship is used in the worked solutions to word problems on cut-and-paste ‘algebra’ on seven different tablets, from Ešnuna, Sippar, Susa, and an unknown location in southern Babylonia.»
^ Kim Plofker (2009). Mathematics in India. Princeton University Press. pp. 17–18. ISBN 978-0-691-12067-6.
^ Carl Benjamin Boyer; Uta C. Merzbach (2011). «China and India». A history of mathematics (3rd ed.). Wiley. p. 229. ISBN 978-0470525487. Quote: [In Sulba-sutras,] we find rules for the construction of right angles by means of triples of cords the lengths of which form Pythagorean triages, such as 3, 4, and 5, or 5, 12, and 13, or 8, 15, and 17, or 12, 35, and 37. Although Mesopotamian influence in the Sulvasũtras is not unlikely, we know of no conclusive evidence for or against this. Aspastamba knew that the square on the diagonal of a rectangle is equal to the sum of the squares on the two adjacent sides. Less easily explained is another rule given by Apastamba – one that strongly resembles some of the geometric algebra in Book II of Euclid’s Elements. (…)
^ Proclus (1970). A Commentary of the First Book of Euclid’s Elements. Translated by Morrow, Glenn R. Princeton University Press. 428.6.
^ (Euclid 1956, p. 351) page 351
^ (Heath 1921, Vol I, p. 144): «Though this is the proposition universally associated by tradition with the name of Pythagoras, no really trustworthy evidence exists that it was actually discovered by him. The comparatively late writers who attribute it to him add the story that he sacrificed an ox to celebrate his discovery.»
^
An extensive discussion of the historical evidence is provided in (Euclid 1956, p. 351) page=351
^
Asger Aaboe (1997). Episodes from the early history of mathematics. Mathematical Association of America. p. 51. ISBN 0-88385-613-1. …it is not until Euclid that we find a logical sequence of general theorems with proper proofs.
^
Robert P. Crease (2008). The great equations: breakthroughs in science from Pythagoras to Heisenberg. W W Norton & Co. p. 25. ISBN 978-0-393-06204-5.
^
A rather extensive discussion of the origins of the various texts in the Zhou Bi is provided by Christopher Cullen (2007). Astronomy and Mathematics in Ancient China: The ‘Zhou Bi Suan Jing’. Cambridge University Press. pp. 139 ff. ISBN 978-0-521-03537-8.
^
This work is a compilation of 246 problems, some of which survived the book burning of 213 BC, and was put in final form before 100 AD. It was extensively commented upon by Liu Hui in 263 AD. Philip D. Straffin Jr. (2004). «Liu Hui and the first golden age of Chinese mathematics». In Marlow Anderson; Victor J. Katz; Robin J. Wilson (eds.). Sherlock Holmes in Babylon: and other tales of mathematical history. Mathematical Association of America. pp. 69 ff. ISBN 0-88385-546-1. See particularly §3: Nine chapters on the mathematical art, pp. 71 ff.
^
Kangshen Shen; John N. Crossley; Anthony Wah-Cheung Lun (1999). The nine chapters on the mathematical art: companion and commentary. Oxford University Press. p. 488. ISBN 0-19-853936-3.
^
In particular, Li Jimin; see Centaurus, Volume 39. Copenhagen: Munksgaard. 1997. pp. 193, 205.
^
Chen, Cheng-Yih (1996). «§3.3.4 Chén Zǐ’s formula and the Chóng-Chã method; Figure 40». Early Chinese work in natural science: a re-examination of the physics of motion, acoustics, astronomy and scientific thoughts. Hong Kong University Press. p. 142. ISBN 962-209-385-X.
^
Wen-tsün Wu (2008). «The Gougu theorem». Selected works of Wen-tsün Wu. World Scientific. p. 158. ISBN 978-981-279-107-8.

Works cited

Bell, John L. (1999). The Art of the Intelligible: An Elementary Survey of Mathematics in its Conceptual Development. Kluwer. ISBN 0-7923-5972-0.
Euclid (1956). The Thirteen Books of Euclid’s Elements, Translated from the Text of Heiberg, with Introduction and Commentary. Vol. 1 (Books I and II). Translated by Heath, Thomas L. (Reprint of 2nd (1925) ed.). Dover. On-line text at archive.org
Heath, Sir Thomas (1921). «The ‘Theorem of Pythagoras’«. A History of Greek Mathematics (2 Vols.) (Dover Publications, Inc. (1981) ed.). Clarendon Press, Oxford. pp. 144 ff. ISBN 0-486-24073-8.
Libeskind, Shlomo (2008). Euclidean and transformational geometry: a deductive inquiry. Jones & Bartlett Learning. ISBN 978-0-7637-4366-6. This high-school geometry text covers many of the topics in this WP article.
Loomis, Elisha Scott (1968). The Pythagorean proposition (2nd ed.). The National Council of Teachers of Mathematics. ISBN 978-0-87353-036-1. For full text of 2nd edition of 1940, see Elisha Scott Loomis. «The Pythagorean proposition: its demonstrations analyzed and classified, and bibliography of sources for data of the four kinds of proofs» (PDF). Education Resources Information Center. Institute of Education Sciences (IES) of the U.S. Department of Education. Retrieved 2010-05-04. Originally published in 1940 and reprinted in 1968 by National Council of Teachers of Mathematics, ISBN 0-87353-036-5.
Maor, Eli (2007). The Pythagorean Theorem: A 4,000-Year History. Princeton, New Jersey: Princeton University Press. ISBN 978-0-691-12526-8.
Neugebauer, Otto (1969). The exact sciences in antiquity. Acta Historica Scientiarum Naturalium et Medicinalium. Vol. 9 (Republication of 1957 Brown University Press 2nd ed.). Courier Dover Publications. pp. 1–191. ISBN 0-486-22332-9. PMID 14884919.
Robson, Eleanor and Jacqueline Stedall, eds., The Oxford Handbook of the History of Mathematics, Oxford: Oxford University Press, 2009. pp. vii + 918. ISBN 978-0-19-921312-2.
Stillwell, John (1989). Mathematics and Its History. Springer-Verlag. ISBN 0-387-96981-0. Also ISBN 3-540-96981-0.
Swetz, Frank; Kao, T. I. (1977). Was Pythagoras Chinese?: An Examination of Right Triangle Theory in Ancient China. Pennsylvania State University Press. ISBN 0-271-01238-2.
van der Waerden, Bartel Leendert (1983). Geometry and Algebra in Ancient Civilizations. Springer. ISBN 3-540-12159-5. Pythagorean triples Babylonian scribes van der Waerden.

External links

Pythagorean theorem at ProofWiki

Euclid (1997) [c. 300 BC]. David E. Joyce (ed.). Elements. Retrieved 2006-08-30. In HTML with Java-based interactive figures.
«Pythagorean theorem». Encyclopedia of Mathematics. EMS Press. 2001 [1994].
History topic: Pythagoras’s theorem in Babylonian mathematics
Interactive links:
- Interactive proof in Java of the Pythagorean theorem
- Another interactive proof in Java of the Pythagorean theorem
- Pythagorean theorem with interactive animation
- Animated, non-algebraic, and user-paced Pythagorean theorem
Pythagorean theorem water demo on YouTube
Pythagorean theorem (more than 70 proofs from cut-the-knot)
Weisstein, Eric W. «Pythagorean theorem». MathWorld.

Источник

Pythagorean theorem


Type	Theorem
Field	Euclidean geometry
Statement	The sum of the areas of the two squares on the legs (a and b) equals the area of the square on the hypotenuse (c).
Symbolic statement	$a^{2}+b^{2}=c^{2}$
Generalizations	Law of cosines Solid geometry Non-Euclidean geometry Differential geometry
Consequences	Pythagorean triple Reciprocal Pythagorean theorem Complex number Euclidean distance Pythagorean trigonometric identity

$a^{2}+b^{2}=c^{2},$

Other forms of the theorem

If c denotes the length of the hypotenuse and a and b denote the two lengths of the legs of a right triangle, then the Pythagorean theorem can be expressed as the Pythagorean equation:

${displaystyle a^{2}+b^{2}=c^{2}.}$

If only the lengths of the legs of the right triangle are known but not the hypotenuse, then the length of the hypotenuse can be calculated with the equation

${displaystyle c={sqrt {a^{2}+b^{2}}}.}$

If the length of the hypotenuse and of one leg is known, then the length of the other leg can be calculated as

${displaystyle a={sqrt {c^{2}-b^{2}}}}$

${displaystyle b={sqrt {c^{2}-a^{2}}}.}$

Proofs using constructed squares

Rearrangement proofs

Algebraic proofs

${displaystyle (b+a)^{2}=c^{2}+4{frac {ab}{2}}=c^{2}+2ab,}$

giving

${displaystyle c^{2}=(b+a)^{2}-2ab=b^{2}+2ab+a^{2}-2ab=a^{2}+b^{2}.}$

${displaystyle (b-a)^{2}+4{frac {ab}{2}}=(b-a)^{2}+2ab=b^{2}-2ab+a^{2}+2ab=a^{2}+b^{2}.}$

But this is a square with side c and area c², so

${displaystyle c^{2}=a^{2}+b^{2}.}$

Other proofs of the theorem

This theorem may have more known proofs than any other (the law of quadratic reciprocity being another contender for that distinction); the book The Pythagorean Proposition contains 370 proofs.^[7]

Proof using similar triangles

${displaystyle {frac {BC}{AB}}={frac {BH}{BC}}{text{ and }}{frac {AC}{AB}}={frac {AH}{AC}}.}$

The first result equates the cosines of the angles θ, whereas the second result equates their sines.

These ratios can be written as

${displaystyle BC^{2}=ABtimes BH{text{ and }}AC^{2}=ABtimes AH.}$

Summing these two equalities results in

${displaystyle BC^{2}+AC^{2}=ABtimes BH+ABtimes AH=AB(AH+BH)=AB^{2},}$

which, after simplification, demonstrates the Pythagorean theorem:

${displaystyle BC^{2}+AC^{2}=AB^{2}.}$

Euclid’s proof

Proof in Euclid’s Elements

For the formal proof, we require four elementary lemmata:

If two triangles have two sides of the one equal to two sides of the other, each to each, and the angles included by those sides equal, then the triangles are congruent (side-angle-side).
The area of a triangle is half the area of any parallelogram on the same base and having the same altitude.
The area of a rectangle is equal to the product of two adjacent sides.
The area of a square is equal to the product of two of its sides (follows from 3).

Next, each top square is related to a triangle congruent with another triangle related in turn to one of two rectangles making up the lower square.^[10]

Illustration including the new lines

Showing the two congruent triangles of half the area of rectangle BDLK and square BAGF

The proof is as follows:

Let ACB be a right-angled triangle with right angle CAB.
On each of the sides BC, AB, and CA, squares are drawn, CBDE, BAGF, and ACIH, in that order. The construction of squares requires the immediately preceding theorems in Euclid, and depends upon the parallel postulate.^[11]
From A, draw a line parallel to BD and CE. It will perpendicularly intersect BC and DE at K and L, respectively.
Join CF and AD, to form the triangles BCF and BDA.
Angles CAB and BAG are both right angles; therefore C, A, and G are collinear.
Angles CBD and FBA are both right angles; therefore angle ABD equals angle FBC, since both are the sum of a right angle and angle ABC.
Since AB is equal to FB, BD is equal to BC and angle ABD equals angle FBC, triangle ABD must be congruent to triangle FBC.
Since A-K-L is a straight line, parallel to BD, then rectangle BDLK has twice the area of triangle ABD because they share the base BD and have the same altitude BK, i.e., a line normal to their common base, connecting the parallel lines BD and AL. (lemma 2)
Since C is collinear with A and G, and this line is parallel to FB, then square BAGF must be twice in area to triangle FBC.
Therefore, rectangle BDLK must have the same area as square BAGF = AB².
By applying steps 3 to 10 to the other side of the figure, it can be similarly shown that rectangle CKLE must have the same area as square ACIH = AC².
Adding these two results, AB² + AC² = BD × BK + KL × KC
Since BD = KL, BD × BK + KL × KC = BD(BK + KC) = BD × BC
Therefore, AB² + AC² = BC², since CBDE is a square.

Proofs by dissection and rearrangement

Diagram of the two algebraic proofs

Animation showing proof by rearrangement of four identical right triangles

Animation showing another proof by rearrangement

Proof using an elaborate rearrangement

Einstein’s proof by dissection without rearrangement

Right triangle on the hypotenuse dissected into two similar right triangles on the legs, according to Einstein’s proof

Proof by area-preserving shearing

Visual proof of the Pythagorean theorem by area-preserving shearing.

Algebraic proofs

${frac {1}{2}}(b+a)^{2}.$

Proof using differentials

One can arrive at the Pythagorean theorem by studying how changes in a side produce a change in the hypotenuse and employing calculus.^[22]^[23]^[24]

Diagram for differential proof

${displaystyle {frac {dy}{dx}}={frac {x}{y}}.}$

This can be rewritten as , which is a differential equation that can be solved by direct integration:

giving

${displaystyle y^{2}=x^{2}+C.}$

The constant can be deduced from x = 0, y = a to give the equation

${displaystyle y^{2}=x^{2}+a^{2}.}$

This is more of an intuitive proof than a formal one: it can be made more rigorous if proper limits are used in place of dx and dy.

Converse

The converse of the theorem is also true:^[25]

Given a triangle with sides of length a, b, and c, if a² + b² = c², then the angle between sides a and b is a right angle.

For any three positive real numbers a, b, and c such that a² + b² = c², there exists a triangle with sides a, b and c as a consequence of the converse of the triangle inequality.

It can be proven using the law of cosines or as follows:

The above proof of the converse makes use of the Pythagorean theorem itself. The converse can also be proven without assuming the Pythagorean theorem.^[27]^[28]

If a² + b² = c², then the triangle is right.
If a² + b² > c², then the triangle is acute.
If a² + b² < c², then the triangle is obtuse.